
solar workshop notes
19 sep 2005
here are 26 pages of notes in advance for a workshop at the first
pennsylvania renewable energy festival this saturday morning
from 912, september 24, 2005 near allentown, pa. see
http://www.paenergyfest.com/workshopinfo.shtml.
comments welcome...
nick
notes for a pennsylvania renewable energy festival workshop
on solar house heating and natural cooling techniques
kempton, pa september 24, 2005
written by nick pine, with drew gillett and rich komp
debatable conclusions
1. heat flows like electricity.
2. solar heat can be 100 times cheaper than solar electricity.
3. superinsulated houses have to be very small or very large.
4. direct gain houses can be improved.
5. indirect gain can be more efficient.
6. we might store heat in the ceiling.
7. we might have a separate cloudyday heat store.
8. low temp heat storage and distribution are difficult.
9. shurcliff's lung might be a good airair heat exchanger.
10. greywater heat exchangers, big fins and solar ponds can help.
11. we might also gather heat from pvs.
12. smart ventilation can be helpful.
13. swamp coolers can be improved.
0.0 introduction
the us has 5% of the world's population and consumes 26% of the world's
energy. house heating and cooling accounts for about one third of that.
in 1980, "envelope house" inventor tom smith said:
it's a snap to save energy in the us. as soon as more people become
involved in the basic math of heat transfer and get a gutlevel,
as well as intellectual, grasp on how a house works, solution after
solution will appear.
this workshop aims at improving that grasp, which we can control better
than our us cheap energy policy... if we paid related costs of healthcare
and air pollution and gulf wars at the pump, gasoline would be a lot more
expensive. drew says this writeup needs exercises for the reader. ok:
exercise 0.1: the us consumed 21 million 42 gallon $41 barrels
of oil per day in 2004. what goes into the real cost per gallon?
(debatable answers appear at the end of these notes :)
most people think "electricity" when they hear "energy," even though most
houses need more heating energy than electrical energy (the ratio is 1:1
in hawaii and 5:1 in vermont.) it's easy to shrink the small electrical
slice of the home energy pie with compact fluorescent (cf) lights and more
efficient appliances. solar heat can be very inexpensive compared to solar
electricity. pv panels at $3 per peak watt cost 150x more than polycarbonate
glazing at $1/50w = 0.02/pw. and sunspaces add floorspace to a house.
a square foot of "solar collector" only collects about $1/year at $1/gallon
so anything (except pvs??? :) that costs more than $10/ft^2 (half labor)
and only collects energy with no other purpose seems economicallydoomed...
exercise 0.2: should we a) replace a 60 w bulb with a 14 watt cf or
b) buy 6014 = 46 additional watts of pv power?
most of us "know" how to design passive solar houses with wellestablished
rules of thumb, but let's relax and take a fresh look from a standpoint
of basic physics...
berlin is a nice town and there were many opportunities for a student to
spend his time in an agreeable manner, for instance with the nice girls.
but instead of that we had to perform big and awful calculations.
konrad zuse, inventor of the 1936 z1 computer
overview
this is a workshop on "ohm's law for heatflow" with applications to solar
water and house heating and natural cooling. we'll discuss a solar pond and
a simple greywater heat exchanger, some inexpensive plastic pipe coiled
inside a 55gallon drum. with hot water bursts of 13 gallons or less, it
could be 97% efficient. if it is, why bother with solar hot water?
we'll provide arithmetic tools and data and strategies needed to sitebuild
effective house heating and cooling systems using inexpensive materials and
skills. participants will need some familiarity with high school algebra.
we'll discuss power, energy, heatflow, and overnight and cloudy day heat
storage at a highschool math and physics level, with insulation values
and heat capacities of materials, simple equations involving time constants,
evaporative and night ventilation cooling, passive and lowenergy solar
heating, climate data, and schemes for houses that are 100% solarheated
and naturally cooled, by design. we'll provide a calculator (steve baer
says "throw away your calculator." :) and a cdrom. promising techniques
include solar closets, trickle collectors, "pancake houses," soap bubble
foam insulation, and solar attics, including systems to collect heat and
electricity from watercooled standard pv panels.
rich komp is president of the maine solar energy association and a pv author
with a pchem phd, drew gillett is a professional engineer with civil
engineering and architectural degrees, and i'm an ee by training.
disclaimer
some of the techniques we describe are experimental. some have never been
tried. we do not accept responsibility for their safety or functionality.
1. power and energy
energy is the stuff we pay for, measured in joules or watthours or
kilowatthours (kwh) or calories or "british thermal units" (btu), no
longer used in britain :) the british now use joules or kwh. a btu is
a quantity of heat, about the same as the energy in a kitchen match or
a mousehour. one btu can heat one pound (16 ounces) of water one degree f.
one calorie (capital c, 4.19 kilojoules) can heat one kilogram of water 1 c.
exercise 1.1: how many btu [joules] are needed to heat 8 ounces [0.25 kg]
of water from 50 to 212 f [10 to 100 c] to make a cup of tea? [the brackets
describe _comparable but not identical_ metric exercises.]
power is the rate of energy flow over time. a mere number, vs the stuff we
pay for. energy is power times time. one watthour of energy is equivalent
to 3.41 btu. if energy were miles traveled, power would be miles per hour.
if energy were a paycheck, power would be an hourly rate of pay.
exercise 1.2: how long would it take to heat the tea water with
a 300 w immersion heater?
we might check this with an immersion heater and a watch and a $100 raytek
ir thermometer. or a hobo from onset computer corp (1800loggers.) their
$119 batterypowered u12013 hobo is about the size of a matchbox. it can
record 43,000 12bit samples at 1 second to 18 hour intervals of its own
temperature and relative humidity (rh), with jacks for 2 more temperature
probes or other devices on cables, and upload them to a pc spreadsheet via
a usb port.
people often confuse power and energy, as in "my house uses lots of power"
(vs energy) or "my furnace capacity is 50,000 btu," (vs btu/h.) power is
measured in watts or kilowatts (kw.) unlike energy, it can't be used or
consumed.
people confuse heat and temperature, too. a bathtub full of hot water
contains a lot of useful house heat, compared to a candle, but the candle
is much hotter. a lower minimum usable temperature increases useful heat.
temperature is a measure of heat intensity. a 12volt 100 amphour 50 pound
automobile battery stores 267 times more energy (12vx100ah = 1200 wh) than
a 9volt 500 milliamphour (9vx0.5ah = 4.5 wh) 2 ounce transistor radio
battery, at a lower voltage (ie "electrical temperature.") the $40 battery
can store about 200 kwh over its lifetime, at 20 cents/kwh. a $1 cubic foot
of water cooling from 130 to 80 f stores (130f80f)64btu/f = 3200 btu, ie
about 1 kwh, with a much longer lifetime and simpler i/o.
2. rich komp, ohm, and newton
rich komp (who is still alive) says heat moves by conduction (a hot frying
pan handle), convection (including air movement), radiation (the sun brings
about 1000 watts per square meter or 300 btu per hour per square foot on
a clear day at noon in the sahara), and phase change (144 btu melts a pound
of ice and 1000 btu evaporates a pound of water.)
about 300 years ago, isaac newton said the amount of heat that flows through
a wall is proportional to its area and the temperature difference from one
side to the other and its thermal conductance. about 100 years later, georg
ohm said the same about electricity: v = ir, ie a current i in amps times a
resistance r in ohms produces a voltage difference v. electrical conductance
is measured on "mhos," which is ohms spelled backwards (or "siemens" which
is snemeis spelled backwards :) if 6 amps flows through a 2 ohm resistor,
we'll see v = ir = 6ax2ohms = 12 volts across it. another example: 120 volts
across 48 ohms makes i = v/r = 120v/48ohms = 2.5 amps flow, with electrical
power p = iv = 2.5ax120v = 300 watts. (these units are capitalized only when
abbreviated, a vs amperes, v vs volts, and so on.)
exercise 2.1: if 24 a flows through a 12 v headlamp, what's the resistance?
3. thermal ohms?
ohm's law for heatflow (aka newton's law of cooling) uses a temperature
difference instead of a voltage difference. heatflow is measured in units
of power, in watts or btu per hour. there's no such thing as a thermal
"ohm." the closest thing is the us "rvalue" stamped on foamboards and
batts in hardware stores.
beadboard (expanded white polystyrene coffee cup material) has a us rvalue
of 4 (ft^2fh/btu) per inch (in these notes, all rvalues are us unless
otherwise specified.) blue, pink or green styrofoam board has us r5/inch.
so does air, for downward heatflow. the slowmoving indoor and windier
outdoor air films near a single layer of glass have a combined us rvalue
of about 1. a smooth square foot of surface in slowmoving air loses about
1.5 btu/hf, with a u1.5 or an r2/3 airfilm resistance. a rough square foot
of surface in v mph air loses about 2+v/2 btu/hf. larger objects have lower
airfilm conductances, since air warms or cools more as it passes over them,
which reduces the temperature difference between the air and the surface.
tiny cold soap bubbles (1/16" at 50 f) have about r3 per inch. bill sturm
filled the space between two polyethylene film covers of his calgary
greenhouse with air during the day and soap bubble foam insulation at night
and measured an 82% propane energy savings with and without the foam on
20 f nights, without much solar energy storage. in one system, air from
a shop vac makes bubbles from a long pvc pipe full of holes in a trough
near the ground containing a 10% detergent solution. when the bubbles
reach a return air vent at the top of the greenhouse at night, they push
on a piece of window screen and a microswitch turns off the shop vac until
the bubbles collapse a bit in a few minutes, and the shop vac runs for
a few more seconds as needed. bill thinks about heating poly film refugee
shelters this way in cold climates.
fiberglass has r3.5/inch, or half that, if it contains 2% moisture (which
it might, in a cold climate, with some holes in a vapor barrier and
condensation), or even less, if air circulates within it, in very cold
places. but rvalues are not quite thermal ohms. to find the thermal
resistance of a wall, divide the rvalue by the area. an 8'x10' us r20
wall has a resistance of r20/(8'x10') = 0.25 fh/btu. we might call this
"0.25 fhubs" or "4 buhfs." we can add buhfs for different kinds of house
walls and windows like resistors in parallel and add fhubs for series
layers of wall insulation.
exercise 3.1: if 6 btu/h [2 watts] of heat power flows through a wall with
a 12 f [7 c] temp diff, what's the wall's thermal resistance in fhubs [c/w]?
exercise 3.2: what's the conductance of an 8'x16' [2mx5m] r10 [metric r2]
wall?
if it's 70 f indoors and 30 f outdoors, (70f30f)/5fh/btu= 8 btu/h [2.3
watts] of heat power flows through 1 ft^2 of r5 wall. but stud walls have
lower stud resistances (r1/inch "thermal bridging") in parallel with the
insulation resistance, and drywall and sheathing on each side of the wall
act as stud fins for heat collection and distribution, which lowers the
overall rvalue.
ignoring the fins, we can look at a 10.67 ft^2 16"x8' wall section with r13
insulation framed with r1 per inch 2x4s on all edges as a "stud conductor"
with (16/12+8)1.5/12 = 1.17 ft^2 of stud surface in parallel with a
10.671.17 = 9.5 ft^2 "insulation conductor." the studs have a 1/(r1x3.5")
= us u0.286 uvalue and the insulation has 1/r13 = u0.0769. the combined
conductance is 1.17x0.286+9.5x0.0769 = 1.07 btu/hf, for an effective us
rvalue of 10.67ft^2/1.07 buhf = r10.0, vs r13, without the studs.
structural insulated panels (sips, glued plywoodfoamplywood sandwiches)
have less thermal bridging and fewer air leaks. so do walls with plywood
ijoists used as studs and loosefill insulation (as used by me al eggen,
ktl14@mindspring.org) and walls with a layer of foamboard insulation over
the studs. an 8'x24' r24 6" sip wall with a 40 f temperature difference
would allow (70f30f)8'x24'/r24 = 320 btu/h of heatflow.
metric (european, canadian, australian...) uvalues are 5.68 times bigger
than us uvalues. a metric u1 window has 1 w/m^2c of thermal conductance.
it's like a lowloss us r5.68 window. a 2 m^2 metric u1 window with 20 c
air on one side and 5 c air on the other would pass (20c5c)2m^2x1w/m^2c
= 30 watts of heat power.
exercise 3.3: how much heat flows through a 2mx6m [8'x16'] metric u0.5
[us u0.088] wall with a 20 c [36 f] temperature difference?
exercise 3.4: how much heat would flow through a 3'x4' us u0.25 window
with 70 f air inside and 30 f air outside?
exercise 3.5: how much heat flows through a 24'x32' [7mx10m] r64
[metric u0.089] ceiling with a 40 f [22 c] temperature difference?
4. a threedog house?
now we can talk about superinsulated houses. they need to be small, like
sleeping bags. can a person heat a house with the help of a few dogs?
an ashrae (american society of heating, refrigeration and ac engineers)
standard 154 pound 19.6 ft^2 human at rest makes about 350 btu/h, like
a 100 w light bulb...
exercise 4.1 how big can an l' us r10 cube be, if it's 70 f inside and
30 f outside, with six outdoor faces, and it's heated by one person?
with r20 walls, l = sqrt(350/12) = 5.4'. better, but cramped...
exercise 4.2: how big can it be with the help of a 100 btu/h dog? with
two dogs? with three dogs? with three dogs and r50 strawbale walls?
if internal heat gain grows with volume, superinsulated apartment houses
have minimum sizes. if each family of 8 1.65 btu/h ashraestandard 0.046 lb
mice in a 1 foot cubical room makes 8x1.65 = 13.2 btu/hft^3, what's the
smallest cubical "mouse motel" with r5 external walls that can stay 70 f
on a 30 f day? if 13.2l^3 = (7030)6l^2/r5, l = 48/13.2 = 3.6', say 4’,
with 512 mice in 64 rooms.
exercise 4.3: what’s the smallest size for a mouse motel with r10 walls?
germans build "passive houses" for people like this, with a "passive
house institute" that certifies them. jackson lab in bar harbor, maine
is heated by 972,000 mice, even on 11 f cloudy days :) a 6.61 pound
ashraestandard cat makes 68.02 btu/h. a 50.0 pound normallyactive
ashrae dog makes 354.9 btu/h. a 1,000 pound jersey calf makes 4,000 btu/h.
larger creatures with lower surfacetovolume ratios produce less heat
per pound. in "the return of the solar cat" (patty paw press, 2003) pe
jim augustyn mentions doe's secret $1.6 trillion 100 megaton solar cat
demonstration project "designed to mimic a solar cat's basic method for
capturing energy on a grand scale."
a frugal 100 kwh per month of indoor electrical use (vs the us average of
833 kwh/mo or the uk average of 383 or the indian average of 55) would
add 100kwhx3412/(30dx24h) = 474 btu/h to a person's 300 btu/h, making an
internal heat gain of 474+300 btu/h = (70f30f)6l^2/r20, which makes
l = sqrt(774/12) = 8.03 feet for an r20 cube. with r50 strawbales,
474+300 btu/h = (7030)6l^2/r50 makes l = 12.7 feet max.
exercise 4.4: if n families each use 774 btu/h in 1024 ft^2 of
floorspace with an 8' ceiling inside an l' r20 cube, what's lmin?
but some people define a "solar house" as "one with no other form
of heat," not even electrical usage or creaturesinresidence...
5. the sun, and weather
suppose the r20 8' cube has an a ft^2 r2 window that admits 200 btu/hft^2
of sun. if 200a = (70f30f)(a/2+(6x8'x8'a)/r20) = 18a+768, we can make it
70 f indoors on a 30 f day with an a = 4 ft^2 window, but the temperature
would instantly drop to 30 f when night falls, unless the cube contained
some thermal mass. of course the sun doesn't put a constant 200 btu/hft^2
into the window all day. this is a crude but useful fullsun approximation.
exercise 5.1: what's the steadystate 24hour temperature of an 8' [2m]
r20 [metric r4] cube containing a very large thermal mass with little temp
change over a day and a 4 ft^2 [0.4 m^2] us r2 [metric r0.4] window with
80% solar transmission, if 1000 btu/ft^2/day [3.15 kwh/m^2/day] falls on
the window over a long string of average 30 f [1 c] days?
keeping it warm at night requires a larger south window. the nrel (national
renewable energy lab) solar radiation data manual for buildings (the "blue
book" at http://rredc.nrel.gov) implies that january is the worstcase month
for solar house heating in boulder, co, when 1370 btu/ft^2 of solar heat
falls on a south wall on an average 29.7 f day, and 1370/(6529.7) = 38.8.
december is the worstcase month for solar house heating in portland, or,
where solar heating is harder, with 470/(6540.2) = 19.0. january is the
worstcase month in albuquerque, where solar heating is much easier, with
1640/(6534.2) = 53.2.
pe norman saunders says the "worstcase month" is the one with the least
solar heat per degree day, on average. this is usually december or january.
aerospace engineers often use "worstcase" specs instead of saying "i know
you are going to be very happy with this airplane" or "it will go very far
and very fast and carry a lot of weight." :)
people often wishfully overestimate passive solar performance, saying things
like "we only burn a few cords of wood per year." how vague. what's "a few"?
what kind of wood? a 4'x4'x8' cord of oak with 20% moisture content burned
at 60% efficiency delivers 158 therms of heat (158x10^5 btu), about the same
as 158 gallons of oil. white cedar can only deliver 72 therms. and wood is
ongoing work, compared to solar heat. was it a cold year or a warm year or
an average year?
what's the solar heating fraction of this house?
every day is sunny for george and charlotte britton of lafayette hill.
their 2,900squarefoot house is blessed with energy bills 20 percent
lower than one of comparable size... the design incorporates "passive"
solar principles. there are large double pane windows and sliding glass
doors on the south side. inside, tile floors and a trombe wall absorb
the sun's heat during the day and radiate it at night... a fireplace
on the south wall of the living area provides additional heat during
colder months... britton says "we have a fire every day of the winter."
solar houses with no other form of heat are 100% solarheated, with no
doubt. then it's just a matter of comfort, or temperature swing. you
might buy an inexpensive 100% solarheated tent with a 20 to 120 f
temperature swing :) a house that can keep itself warm in the worstcase
month should do fine in other months. should america's cup boats have
outboard motors? should solar architects pay clients backup heating fuel
bills, if any?
nrel's "blue book" contains longterm monthly average solar weather data
for 239 us locations. nrel's typical meteorological year (tmy2) hourly data
files are useful for simple solar heating simulations with equations from
highschool physics. my 12 dec 2003 "basic tmy2 simulations" posting in
the postlog file on the workshop cd has simple programs for direct gain,
sunspace, ceiling mass, and solar closet houses with night setbacks.
pe howard reichmuth says a house that can pass an hourly tmy2 simulation
with no backup fuel requirement can also survive a 30year hourly simulation
for the same location. but a calculator can be enough, with simple worstcase
monthly average weather data. can we connect these basic insights and
understandings with leed criteria which seem to have more to do with
fengshui and bicycle racks than fossil fuels? people cared more about
heating bills in 1975...
i wish we could circulate hot air between a house and sunspace and stop the
airflow at night with an energy10 simulation, but it looks like that's not
part of the present package (available from www.sbicouncil.org) or future
energy10 improvements. i still think of sbic (aka psic) as crooked masonry
salesmen out to raise the price and cripple performance of solar houses by
loading up sunspaces with thermal mass, but people can change :)
an 8' us r20 cube might be 70 f (eg 75 at dusk and 65 at dawn) over
an average boulder, co december day with an a ft^2 r2 window with 80%
transmission that admits 0.8x1370 = 1096 btu/ft^2. if 1096a/24h
= (7030)(a/2+(6x64a)/r20) = 18a+768, a = 28 ft^2. thermal mass and
a 4'x8' window would do, with a cube conductance of 32ft^2/r2+(6x6432)/r20
= 34 btu/hf, about half window and half walls, like an early los alamos
labs passive solar test cell.
exercise 5.2: what's a in allentown, pa, where 800 btu/ft^2 of sun
falls on a south wall on an average 31.8 f december day?
6. thermal mass and direct gain, aka "direct loss"
water is cheap and heavy, but easily moved. when moving, it has a low
thermal resistance. a square foot of 1" drywall (a "c1" board foot)
stores 1 btu/f, like a pound of water. a 95 lb cubic foot of dry sand
with a 0.191 btu/flb specific heat can store 0.191x95 = 18 btu/f.
adding 40% water by volume would increase this to about 43 btu/fft^3
and let it support something above.
moving water can greatly lower its stagnant r0.4 per inch resistance.
a cubic foot of concrete stores about 25 btu/f, like wet sand, vs 64
for a cubic foot of water or steel, but concrete's r0.2/inch resistance
makes it hard to move heat in and out. a 32 pound 8"x8"x16" hollow
concrete block with 5.8 ft^2 of naked surface has a specific heat of
0.16 btu/flb and stores 0.16x32 = 5 btu/f.
an r fhub cube outside c btu/f of thermal capacitance has a "time constant"
rc = c/g in hours (dimensionally, (fh/btu)/(btu/f) = h.) in rc hours, the
indooroutdoor temp difference decreases to about 1/3 (e^1) of its initial
value. if rc = 24 hours and t(0) = 75 f, t(h) = 30+(7530)e^(h/24) after
h 30 f hours and t(d) = 30+(7530)e^(d) after d days, where e^x is the
inverse of the natural log ln(x) function on a casio fx260 calculator.
t starts at 75 f when e^(0) = 1 and ends up at 30 f (the outdoor temp)
much later, as e^(t) approaches 0. between those times, the exponential
factor gradually squashes the initial temp diff of (7530) = 45 degrees.
exercise 6.1: what's t(d) after 1 30 f cloudy day?
a liter of water weighs 2.2 pounds, so it stores 2.2 btu/f [4.2 kj/kgc or
1.2 wh/kgc.] n 2liter bottles inside an 8' us r20 cube with an 8'x8' r2
south window and g = 64ft^2/r2+5x64ft^2/r20 = 48 btu/hf would make
rc = 4.4n/48/24h = 0.00382n days.
starting at 75 f, t(d) = 30+(7530)e^(d/0.00382n) = 30+(7530)e^(262d/n),
d days later. when 65 = 30+(7530)e^(262d/n), ln((6530)/(7530))
= 262d/n, so n = 262d/ln((6530)/(7530)) = 1042d.
so storing heat for 1 day (d=1) requires 1042 2liter bottles, 2 days takes
2084, and so on. if cloudy days are like coin flips, storing heat for 1 day
makes the cube's solar heating fraction 50% max, with 75% for 2 days, 88%
for 3, 94% for 4, and 97% for 5 cloudy days in a row, like 5 tails in a row,
with a 2^5 = 0.03 probability. we might flip a coin to simulate sun, with
a constant outdoor temp and heads for an average day and tails for a cloudy
day (no sun.) real weather has more persistence, like a 3state (cloudy,
average, clear) markov chain. we might roll a die with 12 for cloudy day,
34 for an average day with an average amount of sun, and 56 for a clear
day with twice the average amount of sun.
but 5x1042 = 5210 is 5 pickup trucks full of bottles, and 23,000 pounds of
water is a good ballast foundation :) and pet bottles leak water vapor.
they might need topping up once a year. if 9 4" diameter by 12" tall bottles
fit in a cubic foot, they would occupy 5210/9 = 579 ft^3 of the cube's 8^3
= 512 ft^3 volume, rather intrusively :) this fraction shrinks with larger
cubes with smaller heatlosing surface to heatstorage volume ratios, so
larger houses are easier to solar heat.
exercise 6.2: what's the time constant of an empty windowless 8' cube with
a 1/2" layer of drywall inside r20 foamboard insulation? if it's 70 f
indoors and 30 f outdoors when we turn off the furnace at 10 pm, what will
the temp be at 7 am? what would it be if we add 1000 concrete blocks?
exercise 6.3: what would it be if we filled it with water?
7. indirect gain and night insulation
how often do we look out of black windows at night? they are often covered
with curtains. with an r20 wall between the cube and a "lowthermalmass
sunspace" containing lots of south windows, we can circulate warm air
between the sunspace and living space during the day and stop the air
circulation at night, so we can have the best of both worlds, the daytime
gain and views and of the window without nighttime and cloudyday loss,
and the window and thermal mass can be smaller, compared to direct gain,
but it's hard to store solar heat from warm air, compared to mass in
direct sun, because of the high airfilm resistance at the mass surface.
exercise 7.1: can we use less than the 5210 2liter bottles in section 6,
with a lowthermalmass sunspace, ie indirect gain? how many are needed
to keep the cube at least 65 f after 5 cloudy days, if it starts at 75 f?
we can stop air circulation at night with a oneway passive light plastic
film damper hung over a vent hole in the r20 wall, with a mesh that only
allows the film to swing open in one direction. i think doug kelbaugh (now
dean of the u. mich architecture school) invented this "7cent solution" in
princeton in 1973. drew thinks he described it in the proceedings of the
first passive solar conference in albuquerque. pe norman saunders says they
need inspecting every two weeks for folded or torn or hungup films, but
automatic systems are nice, in general. over the years, people usually
stop moving movable insulation that requires twiceaday people power,
even the famous outdoor shutter over the drumwall of steve baer's house.
gary reysa built and tested a fine barn heater
with plastic film dampers, described at http://www.builditsolar.com,
which is on our workshop cd.
david delaney invented (on paper) a "floworganizer"
that might replace a plastic film damper. it would allow a downgoing cool
indoor airstream near a window to cross an upgoing warm airstream behind
an absorber mesh.
for room temperature control, the damper might be in series with an
automatic foundation vent like leslielocke's $12 8"x16" afv1b. its
louvers open as air temperature rises, but the bimetallic coil spring
that opens them can be reversed to close the louvers as air temp rises
and adjusted to change its soft threshold temperature by turning the
spring mounting screw. nasa satellites use "deepspace coolers" that
open to radiate heat as needed.
a motorized damper and thermostat could control a room air temp more
accurately. honeywell's $50 6161b1000 damper motor uses 2 watts when
moving and 0 watts when stopped. if it runs 1 minute per day, that's
0.03 wh. it might move with lowpower electronics and a rechargeable
battery with a 120 v charge pump or a 10 milliwatt pv cell. drew says
tamarack tech and thermal technology (john schnebley) made a pvpowered
shutter like this. rich komp would like to help make them in nicaragua.
fans use more power, but can work with accurate room temp thermostats, and
they can double the collection efficiency of a lowtemp sunspace, compared
to natural thermosyphoning air. and fans can work through smaller holes
than passive dampers, with less conduction loss to the sunspace at night.
8. airflow and heatflow
one btu can raise the temperature of 55 cubic feet of 70 f air 1 f, with
a specific heat of 0.24 btu/lbf [1 kj/kgc or 0.28 wh/kgc], so 1 cubic
foot per minute (cfm) of airflow with a 1 f temp diff moves about 1 (60/55)
btu per hour of heat. a 1 liter/second airstream with a 1 c temp diff moves
about 1.2 w. ashrae says a person needs 15 cfm [7.1 l/s] of outdoor air
to stay healthy. if this just leaks through a house, it adds about 15
btu/hf to its thermal conductance, but the house may leak less on a warm
still day. an airair heat exchanger can avoid this by preheating incoming
cold air with outgoing warm air.
bill shurcliff proposed attaching a "lung" (picture a giant bellows) to
the outside of a house, with a fan that periodically inflates and deflates
the lung with house air, thus turning all the cracks and crevices in the
house envelope into bidirectional heat exchangers with latent heat recovery,
as in a camel's nose. an "infinite virtual lung" might divide a house into
2 partitions with a fan between them that periodically reverses. this could
be efficient, done slowly, with lots of heat exchange area. (an exhaust fan
or stackeffect chimney with scandinavianstyle "breathing walls" seems less
efficient, with no heat recovered from exhaust air.)
if every 10'x10' wall section has a 4x10'x6"deepx1/32"wide perimeter crack
with 40/32/12 = 0.104 ft^2 of crosssectional area, a 4096 ft^2 envelope
would have 4096/100x0.104 = 4.27 ft^2. if 30 cfm flows through it, the air
speed would be 2x30/4.27 = 14 fpm. if each section has 40x0.5x2 = 40 ft^2
of heat exchange surface, cmin = 30 and ntu = au/cmin = 4096/100x40x1.5/30
= 82 and e = 1exp(82). very close to 100% efficiency :)
lbnl tested a finite lung in the 80s, but the lung volume was small compared
to the stud cavity volume, so there was little fresh air exchange. they
aren't able to test it now, since their funding was cut by a factor of four.
someone else might, with a humidistat and lasko's $50 2155 16" reversible
fan (61 watts at 1360 cfm on high speed) and their 2a179 $88.15 programmable
cycle timer and its $4.37 5x852 octal socket.
what is the mean size and standard deviation of house envelope cracks?
a few big holes or cracks could make this work poorly. are envelope cracks
small in volume all the way through, or do they admit air to a large stud
cavity? what about freezing and condensation?
most us houses leak a lot more than 15 cfm/occupant. an old house might leak
2 air changes per hour (ach), eg 2x2400x8/60 = 640 cfm for a 2400 ft^2 one
story house. a new us house might leak 1 house volume per hour. an "energy
star" house might leak 0.5 ach. nisson and dutt's superinsulated house book
suggests a 0.2 ach target. jeff christian at oak ridge has built fullsize
0.04 ach test houses. we measure leaks by pressurizing and depressurizing
a house to 50 pascals (0.00725 psi or 0.2" h20) with a blower door and often
divide airflow in cfm by 20 to estimate natural air leakage in wintertime.
exercise 8.1: what's the conductance of a 40'60’x8' house with us r30 walls
and an r60 ceiling and 8% of the floorspace as r4 windows and 0.5 ach?
http://www.odpm.gov.uk/stellent/groups/odpm_buildreg/documents/page/odpm_
breg_600356.pdf (with a linewrap) is a 1999 uk report. page 2 says a 1981
canadian housing development holds the world record for low air leakage.
page 5 mentions the world's tightest voluntary standard, canada's ideas
(post r2000) 0.15 m^3/h per m^2 of envelope at 50 pa, for a natural air
leakage of 2.5 cfm, or 0.008 ach for a 2400 ft^2 1story house :)
the blower door as we know and love it today springs from technology
first used in sweden in 1977, where it was actually a blower window.
the idea migrated to the united states with ake blomsterberg, who came
to princeton university to do research in 1979...
the princeton researchers decided to mount the fan in a door because door
sizes are more uniform than windows... the researchers found that hidden
leaks accounted for a greater proportion of air leakage in a home than
the more obvious culprits, such as windows, doors, and electrical outlets,
a giant leap forward in our understanding of how a house operates...
a monster blower door is being used to test large residential and
commercial buildings in canada. the super sucker is a whopping 55,000 cfm
fan that is 40 ft long and 5 ft in diameter. it is transported to the
site on a flatbed trailer. it takes a team of five people [with safety
belts?] to hook it up to a pair of double doors and perform the test.
from: http://hem.dis.anl.gov/eehem/95/951109.html
one empirical formula says an h foot chimney with a ft^2 vents at
the top and bottom and an average temp ti (f) inside and to outside
has q = 16.6asqrt(hdt) cfm of airflow, where dt = tito. the heatflow
is qdt = 16.6asqrt(h)dt^1.5 btu/h, approximately.
a square foot of r1 vertical sunspace glazing with 90% transmission would
gain 0.9x800 = 720 btu over 6 hours on an average december day in allentown,
or more, with reflective ground to the south. with an atn(490/800) = 31
degree tilt to the south, it would gain 0.9sqrt(490^2+800^2) = 844 btu/day.
it could be one layer of clear flat ge lexan polycarbonate plastic, which
comes in 0.020"x49"x50' rolls and costs about $1.50 per square foot, or
one layer of corrugated dynaglas "solar siding," a greenhouse roofing
material which costs about $1/ft^2. both last at least 10 years. we might
make an 8' long x 8' radius quartercylindrical sunspace with 3 $5 bows
on 4' centers by bending 2 12' 1x3s into an 8' radius, with 1x3 spacer
blocks and screws every 2'. a freestanding greenhouse might have 4year
greenhouse polyethylene film glazing (which costs about 5 cents/ft^2 in
wide rolls) stretched over slightlycurved bows to avoid wind fatigue,
in a 12' equilateral triangle, hinged at the top.
this could be a food and heat producing greenhouse like bill yanda's or
tom lawand's. pe howard reichmuth's ecotope greenhouse near seattle has
a steep transparent south wall and a reflective parabolic north wall that
concentrates sun into a water trench. greenhouses are more humid than
houses, and they need to be warmer at night to avoid freezing plants, and
it's hard to insulate them at night and also provide light for plants.
filling the space between two plastic film covers with air during the day
and soap bubble foam at night is useful. engineer bob quist in toronto
has developed a standard "replacement foam insulation" system for venlo
glass greenhouses (the most popular brand in the netherlands.)
with a ft^2 of us r1 sunspace glazing and lots of thermal mass, we can keep
an 8' r20 cube 70 f over an average 24h 31.8 f december day with a 39.2 max
in allentown if 720a = 6h(7031.8)a/r1 (the daytime sunspace loss) +
18h(7031.8)a/r20 (the nighttime sunspace loss) + 24h(7031.8)(6x64a)/r20
(the 24hour loss from the rest of the cube), which makes a = 35 ft^2, eg
a 5'x7'window, with a 6x64ft^2/r20 = 19.2 btu/hf cloudyday conductance.
to size the sunspace vents, we might figure that 0.9x250 = 225 btu/hft^2
of peak sun enters a square foot of r1 sunspace glazing and 70 f air near
the glazing (on the south side of a dark screen north of the glazing, with
warmer air north of the screen) loses (7035)1ft^2/r1 = 35 btu/h, for a net
gain of 190 btu/hft^2, or 6.7k btu/h [1.1 kw] for 35 ft^2. if 70 f room
air enters the sunspace through a lower vent and exits into the house at
120 f through a vent 8' above, the average temp inside the sunspace is
97.5 f, and 6.7k btu/h = 16.6asqrt(8')(97.570)^1.5 makes a = 0.98 ft^2.
9. store the heat with less mass in the ceiling and a larger temp swing?
we might warm ceiling mass (eg soil "pugging" in scotland) with hot air
from a sunspace. ignoring sunspace vent and ceiling airfilm resistances,
on an average december day in allentown, an 8' r20 cube with a ceiling
temp t (f) and 8'x8' of r1 sunspace glazing might collect 0.9x800x64
= 46.1k btu and lose about 6h(t32)64ft^2/r1 from glazing during the day
+ 18h(6532)64ft^2/r20 from the glazing at night + 24h(t32)64ft^2/r20
up through the ceiling + 24h(6532)3x64ft^2/r20 from the other 3 walls
at night, which makes t = 46322/460.8 = 101 f, if gain equals loss
on an average day.
if the ceiling conductance to slowmoving air below is 1.5x64 = 96 btu/hf
and the cube needs (7032)19.2 = 730 btu/h of peak heat on a cloudy day,
the ceiling must be at least 70+730/96 = 78 f to provide it. if the average
temp is (101+78)/2 = 89.5 f for 5 cloudy days and the cube loses about
5x24h((6532)4x64ft^2/r20 + (89.532)64ft^2/r20) = 72768 btu, we need
72768/(10178) = 3164 btu/f of ceiling mass, eg 3164/64ft^2 = 49 pounds
(9.5") of water per square foot of ceiling.
or slightly less, using a more accurate differential equation. at ceiling
temp t, i = (t32)64ft^2/r20 + (6532)4x64ft^2/r20 = 3.2t + 320 btu/h flows
from the ceiling mass c, so dt/dt = i/c = at + b = 3.2t/c  320/c, and
a/b = 100, so t(t) = a/b +(t(0)+a/b)e^at = 100 + 201e^(3.2t/c). after
5 days, t(120) = 78 = 100 + 201e^(384/c) makes ln(178/201) =  384/c, so
c = 3160 btu/f.
exercise 9.1: how many inches of water are needed in december in portland,
or when 470 btu/ft^2 falls on a south wall on an average 40.2 f day, for an
8' r32 cube with an 8'x8' r2 sunspace window with 80% solar transmission?
keeping the heat in the ceiling allows the cube to be cooler when vacant,
so stored solar heat can last longer, especially if we reduce the ceiling's
downward heatflow by radiation with a lowemissivity ceiling surface.
exercise 9.2: how might this change if the cube only needs 8h/day of heat?
solar pioneer harold hay built houses with roofponds and movable insulation.
in the barra system, hot sunspace air warms a hollow spancrete ceiling. we
might collect and distribute heat with ceiling fin tubes, pumping cool water
up during the day and thermosyphoning at night, with the help of a slow
ceiling fan.
10. radiation
gustav robert kirchoff (18241887) said all radiation hitting a surface must
be transmitted, absorbed, or reflected. radiation obeyed. t+a+r=1. kirchoff's
identity says emissivity equals absorptivity for opaque black bodies or gray
surfaces with a constant emissivity that doesn't depend on wavelength.
a surface emits se(t^4) of heat flux by radiation, where t is an absolute
temperature in rankine (f+460) or kelvin (c+273) degrees, and s is the
stefanboltzman constant, 0.1714x10^8 btu/ft^2r^4 or 5.660x10^8 w/m^2k^4.
the surface's emissivity e varies from 0 (shiny) to 1 (dull.) most natural
surfaces are close to 1, but heat mirrors have emissivities close to 0.
the net heatflow from a surface at t1 degrees facing a t2 degree surface
is se(t1^4t2^4). for example, a square foot of 80 f trombe wall might
lose 0.1714x10^8((80+460)^4(30+460)^4) = 47 btu/h by radiation on a 30 f
night. in still air, it might lose 1.5(8030) = 75 btu/h by radiation and
convection combined. a "selective surface" can absorb well at short solar
wavelengths (<3 microns) and radiate poorly at longer heat wavelengths
(10 microns at 80 f.) a 100% solarheated house might have thick sips and
radiant floors and a big enough wellinsulated hot water tank to store heat
for 5 cloudy days in a row and lots of $12/ft^2 vertical unglazed stainless
steel es solar roof collectors with durable selective surfaces from
www.energiesolaire.com. with collector and ambient temps tm=30 and ta=0 c
and insolation i = 800 w/m^2 (full sun), x = (tmta)/i = 0.375 makes
e = 0.959 8.91x0.047x^2 = 0.62, ie 62% in their efficiency formula.
exercise 10.1: what's the temperature of a surface
with e = 0.2 in 300 btu/hft^2 sun on a 20 f day?
the most serious mistake was making the outer container of the receiver
of plywood. we thought that the plywood would be sufficiently insulated
from the copper panel which was the receiver proper, that it would not
get too hot. the copper panel was separated from the plywood by 4" of
fiberglass insulation. nevertheless, the plywood caught fire and the unit
was completely destroyed. we suppose this is a success, of sorts.
the copper panel which was plated with chrome black to provide a
selective surface originally had a copper tube fastened to the back by
a high melting point soft solder. when we first attempted to operate
the unit, the soft solder melted, and the tubing became detatched from
the panel. we attempted to repair this failure by silver soldering
copper bars to the copper tube and screwing the bars to the plated
copper sheet. this worked, after a fashion...
the glass window was originally tempered glass. this shattered due to
thermal shock. we replaced it with ordinary window glass. this cracked
due to thermal shock, but we were able to hold it in place well enough
to make some measurements... the measurements we were able to make
before the fire generally confirmed our thinking concerning the design...
from "a solar collector with no convection losses," (a downwardfacing
receiver over a 4:1 concentrating parabolic mirror), by h. hinterberger
and j. o'meara of fermilab, in "sharing the sun," a joint ases/sesc
conference, august 15th20th, winnepeg, volume 2, pp 138145.
if tb is their approximate average temperature, the "linearized radiation
conductance" between 2 surfaces gr = 4setb^3. a 96 f ceiling in a 70 f room
with tb = 543 r has gr= 1.097 btu/hfft^2, roughly r0.9. if our cube needs
(70f30f)19.2btu/hf = 768 btu/h, e(9670)64x1.097 = 768 makes e = 0.42.
we might make about 60% of the ceiling a lowe (0.05) paint or foil surface
and the rest an ordinary surface and let radiation warm the room on an average
day and use a ceiling fan and a thermostat to bring warm air down on cloudy
days. a 72 f ceiling could supply 0.42(7265)64ft^2x1.097 = 206 btu/h of
radiant heat to a 65 f room. the other 672206 = 466 btu/h might come from
q cfm of airflow. view figure 1 below in a fixed font:
1/96 1/q (96+q)/(96q)
72 f wwwwww65 f equivalent to 72www65
> >
466 btu/h 466 btu/h
where (7265)96q/(96+q) = 466, so q = 217 cfm. grainger's $120 48" 315 rpm
86 w 21k cfm 4c853 ceiling fan might move 217 cfm at 217/21kx315 = 3.3 rpm
with 86(217/21k)^3 = 100 microwatts, according to the fan laws :) large
slow fans can be very efficient and quiet. the gossamer ceiling fan develope
by danny parker at the florida solar energy center can move 1907 cfm with 9.1
watts. it might move 217 cfm with 1 average watt, running 11% of the time.
11. even less ceiling mass, with a separate cloudyday store?
if we only want to store 13.8k btu of overnight heat on an average day in
c btu/f in a ceiling, with t(6) = 120+(72120)e^(6x96/c) = 12048e^(576/c)
and (t(6)72)c = 18,432, so c = 384/(1e^(576/c)). c = 384 on the right makes
c = 494 on the left, and plugging that in on the right again makes c = 558,
596, 620, 635, 644, 649, 653, 655, 657, and 657 (whew!), so it looks like we
can store overnight heat with 657/64ft^2 = 10.3 psf (about 2") of water in
the ceiling, with t(6) = 12048e^(576/657) = 100 f.
if the 8' cube needs 4x24(7030)19.2 = 73,728 btu for 4 more cloudy days,
this might come from a "solar closet" (see the cd paper) inside a sunspace.
the heat lost from the closet air heater glazing efficiently heats sunspace
air that heats the cube :) with about 73,728/(12070) = 1475 lb or 184 gal.
or 23 ft^3 of water cooling from 120 f to 70 f over 4 days.
kallwall's "solar battery" was an early solar closet. tom hopper built an
insulated box containing fiberglass water cylinders with doubleglazed
south wall and an insulating curtain (5 layers of aluminized mylar) that
automatically rolled down over the glazing at night. bill shurcliff (in his
1980 brick house thermal shutters and shades book) said this remarkable
mylar curtain (with spacers that unfurled when it deployed) was invented
by the insulating shade co. of branford, cn, and demonstrated at a 9/9/77
exhibition in hartford, cn, and featured in the january 1979 issue of
popular science monthly.
with 1792 pounds of water in 56 10"x10"x13" 4gallon ropak plastic tubs,
a solar closet can supply 73,728 btu as it cools from 120 to 12073728/1792
= 78.9 f, with the tubs stacked 7high and 4wide and 2deep in a 2'x4'x8'
tall closet completely surrounded by insulation, with an air heater with
its own closet vs sunspace glazing over the closet's insulated south wall
and oneway dampers in that wall. with 56x4x10x13/144 = 202 ft^2 of tub
surface and 300 btu/hf (buhfs) of waterair thermal conductance, we have
fig 1 again with a 78.970 = 8.9 f temp diff and a (300+q)/(300q) resistor,
so q = 121 cfm.
with an 8' height difference and 121 cfm = 16.6asqrt(8'(78.970)),
we need 2 vents with a = 0.86 ft^2 for natural airflow into the cube.
as an alternative, the cloudyday heat might come from 3072 pounds of water
inside a 2'x4'x8' tall "shelfbox" with a 2'x4'x2' tall water tank below 18
2'x4' wire shelves on 4" centers, with 2" of water inside a $20 continuous
piece of poly film duct folded to lay flat on each shelf and a small pump to
circulate tank water up through the duct as needed. the tank might have a
plastic pipe coil inside to make hot water for showers, with the help of an
efficient external greywater heat exchanger, eg 300' of 1" plastic pipe
pushed into two coils inside a 35"x23.5"" id 55 gallon drum, if possible.
pushing the pipe into the drum without kinking is awkward but doable.
12. greywater heat exchange, big fins, and solar ponds
about 15 years ago, eric olsen at earthstar manufactured a heat exchanger
with a copper coil in a 55 gallon drum to recover heat in kidney dialysis
centers. drew says professor jane davidson at u minnesota is an expert on
plastic heat exchangers. she says "the efficiency you calculate is actually
effectiveness which is very different from efficiency. a high effectiveness
does not mean a good heat exchanger!" i wonder what she means by that.
gary and i are working on inexpensive "big fins" for water heating in
sunspaces and a solar pond water heater and what might become an
efficient counterflow greywater heat exchanger with heat storage. see
http://builditsolar.com. we are using a new $35 55 gallon lined steel drum
with a strong removable lid (because the drum might end up under 2' of
greywater head, with the inlet and outlet above the lid) and bolt ring
and a 3/4" bung and a 2" bung with a 3/4" threaded knockout, with 100 psi/
73.4 f pipe from pt industries at (800) 44 endot. their pbj10041010001
$60 1"x300'100psi nsfcertified pipe is tested to 500 psi.
lowes sells the rest of the hardware. it's all installed through the lid,
so the drum itself has no holes. here's a tentative parts list:
sales total
# qty price description
25775 1 $5.73 24' of 1.25" sump pump hose (for greywater i/o)
105473 1 1.28 2 ss 1.75" hose clamps (for greywater hose)
54129 2 3.24 1.25" female adapter (greywater barb inlet and outlet)
23859 2 2.36 1.25x1.5" reducing male adapter (bulkhead fittings)
75912 1 0.51 2 1.25" conduit locknuts (bulkhead fittings)
28299 1 1.53 2 1.25" reducing conduit washers (")
22716 1 1.36 1.5" pvc street elbow (horizontal greywater inlet)
23830 1 2.98 10' 1.5" pvc pipe (for 3' greywater outlet dip tube)
the parts above are the greywater plumbing ($18.99.)
23766 4 1.28 3/4" cpvc male adapter (for 1" pipe barbs)
23766 2 0.64 3/4" cpvc male adapter (fresh water i/o)
42000 2 3.84 3/4" fip to 3/4" male hose adapter
23813 1 1.39 10' 3/4" cpvc pipe (for 1"x3/4" fresh water outlet)
23760 2 0.96 3/4" cpvc t (fresh water i/o)
22643 2 0.86 3/4" cpvc street elbow (fresh water i/o)
4  1" 3/4" cpvc pipes (fresh water i/0)
1  3' 3/4" cpvc pipe (fresh water inlet)
22667 2 2.56 2 ss 1.125" hose clamps (fresh water i/o)
219980 1 4.87 10.1 oz dap silicone ultra caulk (bulkhead fittings)
150887 1 3.94 4 oz primer and 4 oz pvc cement
the parts above are fresh water plumbing. subtotal $39.33.
26371 1 6.83 1500 w electric water heater element
22230 1 2.31 1" galvanized t ("nut" for heating element)
61294 1 11.76 single element thermostat with safety
136343 1 0.56 5 1024x3/4" machine screws (mount thermostat with 3)
33368 1 0.37 5 #10 ss flat washers (mount thermostat with 3)
198806 1 1.38 10 #0 rubber faucet washers (mount thermostat with 3)
8763 1 0.67 5 1024 ss nuts (mount thermostat with 3)
the above would make a standalone water heater, if needed. grand total:
$63.21.
for 4 10 min showers per day and 20 minutes of dishwashing at 1.25 gpm we
might heat 75 gallons of 55 f water to 110 with 8x75(11055) = 33k btu with
about 10 kwh worth about $1/day at 10 cents/kwh. if the "heat capacity flow
rate" cmin = cmax = 75gx8/24h = 25 btu/hf and the coil has a = 300pi/12
= 78.5 ft^2 of surface with u = 10 btu/hfft^2 (for an hdpe pipe wall with
slowmoving warm dirty water outside and 8x300pi(1/2/12)^2 = 13 gallons of
water inside), the "number of heat transfer units" for this counterflow heat
exchanger ntu = au/cmin = 78.5ft^2x10btu/hfft^2/25btu/hf = 31.4, so the
"efficiency" e = ntu/(ntu+1) = 97% for hot water usage in bursts of less
than 13 gallons. this works best with equal greywater and cold water flows,
with either a 110 f water heater setting (preferable), or the heat exchanger
output feeding the cold water shower inlet as well as the water heater.
the hazenwilliams equation says l' of d" smooth pipe with g gpm flow has
a 0.0004227lg^1.852d^4.871 psi loss. at 1.25 gpm, the pressure drop for 2
150' coils of 1" pipe is 0.0004227x150x(1.25/2)^1.852x1^4.871 = 0.03 psi.
if greywater leaves a shower drain at 100 f and fresh water enters at 50 f,
the fresh water should leave at 50+0.97(10050) = 98.5 f. warming it further
to 110 f would take 8x75(11098.5) = 6.9k btu/day with 2 kwh worth about
20 cents/at 10 cents/kwh, for a yearly savings of about ($10.20)365 = $292,
or more, with a tighter shower enclosure and higher drain temperature. the
1500 w heater might operate 2kwh/1.5kw = 1.3 hours per day.
so far, we've discovered the steel drum wall needs insulation inside to
preserve stratification because it conducts heat from warm greywater
above to cooler greywater below. we might put foil foamboard with kerfs
(knife cuts partially through the board) inside the drum, with a plastic
film liner to keep it dry. we'd also like to improve incoming greywater
stratification, to let it find its thermal level via the holey dip tube...
zomeworks makes expensive "big fins" aluminum extrusions that snap onto
copper pipes to heat water in sunspaces. the pressurized water inside
the pipes thermosypohons through an insulated tank above, with no pumps,
eat exchangers, controls, or antifreeze. we might use the wrapping jig at
http://www.redrok.com/misc1.htm#wrappingjig to make less expensive big
fins like this:
. .
. . . .
aluminum flashing rivet . . 1/2" . .
............................ . copper . .
............................ . pipe . .
rivet . . . .
. . . .
 . . .
.
 . <foilfaced foamboard
. on the back side?
...then open it up like this: .
. . .
. . . . .
home depot sells dark .rivet . . . .
brownpainted aluminum ~5" ...... . copper . .
roof flashing for $46.50 ...... . pipe . .
for a 50'x2'x0.027" roll. .rivet . . . .
. . . . .
. . .
[view in courier font.] .
 . this solar collector might be
. 60% efficient heating 120 f
 . water inside an 80 f sunspace.
solar water heaters often have expensive pressurized stonelined tanks that
wear out. gary's brilliant idea was replacing the tank with an inexpensive
flat plastic pipe coil heat exchanger in a "solar pond water heater" with
a foamboard lid that also acts as a solar collector. during the day, a very
low power pump circulates pond water a few inches up over a layer of epdm
rubber over the foamboard, and the water drains back at night. the pond is
deep enough to stay hot for a few days. a 4'x8' pond might supply most of
the hot water for a family of 3. this is still in development. we invite
you to build one, or follow its progress on the experimental page at
http://builditsolar.com.
13. other promising solar house heating schemes
harry thomason's trickle collectors were used in hundreds of houses. pump
water up to the ridgeline of a metal roof and trickle it down under a glass
cover to a gutter, then down to a large tank on the ground buried in rocks
to help with waterair heat distribution. he also trickled water over bare
asphalt shingle roofs at night for evaporative cooling. dick bourne at davis
energy systems also does this sort of thing, and lives in a roofpond house
under a few inches of water under floating styrofoam, sprinkled at night.
these days, a hydronic floor with a low waterair thermal resistance in
an airtight house with lots of insulation might be simpler and use less
power for heat distribution. this system needs lots of collector pump power,
and it looks like the roof cover has to be polyethylene film or glass,
since polycarbonate quickly degrades in warm water vapor. we might inflate
a polyethylene film cover over a dark asphalt roof when water is flowing
between them or it's very windy outdoors (>15 mph) or the roof is very hot
(>150 f), with straps over the poly film to prevent outward ballooning.
trickle collectors can only heat water to 80 or 90 f on cold winter days,
so heat storage and distribution tend to be inefficient. an efficient solar
heating system might keep a house warm on an average day with a hydronic
floor and low temp water from a trickle collector and lots of insulation,
and keep the house warm for 5 cloudy days with some higher temp water from
a wellinsulated and seldom used cloudyday store.
exercise 13.1: what's the min floor temp required to keep a house with a
200 btu/hf conductance and a 2400 ft^2 radiant floor 70 f on a 30 f day?
zomeworks may soon have a more efficient "doubleplay" system with plastic
tubes under closelyspaced metal roof standing seams, with a polycarbonate
cover or a selective surface. dawn solar in new hampshire is also working
on something like this.
zomeworks "cool cells" connect water pipes under the ceiling with roof ponds
or radiators that lose heat by natural thermosypnoning at night, which stops
during the day. a system with water in weaker flat poly ducts under the
ceiling might use a 10 watt fountain pump to keep a roofpond full at night
vs thermosyphoning. a roofpond that's dry during the day would consume less
water and kill biological growths with solar heat.
donald wright's habitat for humanity houses near safford arizona use large
hydronic solar collectors with fiberglass window screen between two hypalon
rubber layers for more uniform water flow. but they pump the warm water
under a slab beneath lots of sand with a high thermal resistance, which seems
like a big mistake, thermallyspeaking. adirondack houses also work this way,
but they seem to be mostly woodheated. kachadorian's solar slab is good,
but i doubt it works with thermosyphoning air, as he claims. and with no
insulation above, it can't be much warmer than 70 f without overheating
the occupants. rich komp calls his earlier slab a hypocaust, as in hollow
roman woodfired floors.
a thomason "pancake house" might have a draindown poly film roof pond and
an underfloor poly film pillow for heat distribution. a "concentrating
solar attic" might have a transparent steep south roof and a north roof that
approximates a parabola with 4 or 5 line segments (we want to avoid line
foci) aimed slightly above the horizon to reflect 23 suns down into a
4'wide water trough along the attic floor near the north wall. the trough
might be 30" round polyethylene film greenhouse air duct (about 40 cents per
linear foot) that lays flat to 48", with 12" of water inside during the
day. this might be on top of standard photovoltaic panels on the attic floor.
we need careful layout or some sort of optical mixing for uniform brightness
to avoid inefficient shadows and bright spots on the pvs. cooled to 120 f,
they should have a long lifetime under 23 suns. your milage may vary.
don booth built a beadwall attic with waterbed heat storage in concord, nh.
14. natural cooling
less electrical usage helps, eg reflected sunlight at 200 lumens per watt
instead of fluorescents at 50 lumens per watt. these days, the illuminance
of a welllit building is 50 footcandles (fc)...
to increase the "demand" for more power plants, the power and lighting
industries were very effective in promoting everincreasing illumination
levels and incorporating them into codes. in some cases "required" light
levels were so high that artificial lights had to be used all the time,
regardless of the external climate and availability of natural light.
such lights often heated buildings to the extent that air conditioning
was needed yearround.
from sunlighting as formgiver for architecture,
by william m. c. lam, van nostrand, 1986
....we might provide 50 fc = 50lumens/ft^2x64ft^2 = 3200 lumens with
3200/50 = 64 watts of fluorescents or 16 watts of sunlight. if bright sun
is 8000 fc we only need about 50/8000x64ft^2 = 0.4ft^2 of window for this,
ie 0.6% of the floorspace as windows, with no transmission/reflection loss,
if the sun could be distributed uniformly, or 2%, counting losses and
nonuniformity. or 4%, to have enough light on overcast days.
our 8' cube might have a 1.28 ft^2 clerestory window 8' long and 2" tall on
the south side of the roof near the peak, with a reflective roof underneath
and an overhang that's reflective underneath and a reflective north ceiling.
we might want taller windows with overhangs to admit all beam sun at noon on
the winter solstice and exclude it all on the summer solstice.
at noon on 12/21 in the north hemisphere, sun elevation emin = 90lat23.5
degrees. at noon on 6/21, emax = 90lat+23.5 deg. a horizontal overhang that
projects p' from a south wall d' above the top of the glass of an h' tall
window can completely shade the window on 6/21 and pass all sun on 12/21 if
tan(emin)=d/p and tan(emax)=(h+d)/p, so p=h/(tan(emax)tan(emin)) and d
= ptan(emin). for example, at 40 n. lat, emin = 26.5 degrees and emax = 73.5,
so an h = 8' tall window needs a p = 2.7' overhang d = 1.2' above the top
of the glass.
shading and lightcolored walls help. plants on trellises come to mind.
walls and roofs have more insulation than windows, but they also have much
more surface. some mobile homes have old tires on flat roofs. it pays (@$1)
to collect old tires where i live in pa. a green roof might have weeds
growing in gravel over epdm rubber. it might cool better and use less water
without the weeds, which only cool air. attics and sunspaces need venting.
night ventilation can help, if a house has lots of internal thermal mass
and lots of insulation. ventilate with cool night air and button the house
up during the day and let the thermal mass keep it cool. nrel says july is
the warmest month in boulder, with average 73.5 f days and daily lows and
highs of 58.6 and 88.2 and an average humidity ratio w = 0.009. this is the
number of pounds of water vapor per pound of dry air. it is more constant
over a day than the relative humidity (rh), which depends how much water
the air can hold, which depends on the air temperature.
"comfort" depends on temperature, humidity, air velocity (faster is cooler),
activity (sleeping vs wrestling) and clothing (threepiece suits vs shorts
and a tshirt.) the ashrae comfort zone relates temp and humidity ratio.
experiments have found that people in developed countries are "comfortable"
from about 67 to 81 f, with w = 0.0045 to 0.012. t = 89.41867w is a
"constant comfort" line diagonally down through the zone. with w = 0.009,
t = 72.6 is most comfortable. can we keep our cube in the zone with night
entilation?
we might put n 2liter water bottles inside the cube and remove the roof
to make a "cold trap" at night with no lower temperature limit, or put
a motorized damper near the top that lets warm air flow out of the cube
every night until the inside air temp drops to 70.6 f.
if we model an average boulder july day as a square wave with 12 hours at
(58.6+73.5)/2 = 66 f followed by 12 hours at (73.5+88.2) = 81 f (not very
close to the real sine wave, but maybe more useful than solar architects'
rules of thumb), we have c = 4.4n btu/f in series with its 1.83n thermal
conductance to slow moving air and a 19.2 bhuf cubetooutdoor conductance
that's shunted at night with a q cfm airflow conductance.
1/19.2 1/(1.83n)  
81/66 wwwwww 
   
 1/q 
/ www 4.4n btu/f
as the bottles warm, 74.6 = 81+(70.681)e^(12/rcc) makes the charge time
constant rcc = 24.7 h = 4.4n/19.2, approximately, so n = 108 (recall kim
basinger's weight in "batman"?) and c = 475 btu/h. as the bottles cool,
70.6 = 66+(74.666)e^(12/rcd) makes rcd = 19.2 h. each bottle has about
1.2 ft^2 of surface with a 1.5x1.2 = 1.8 bhuf conductance, so 108 have a
198 bhuf conductance or a 5.06 millifhub thermal resistance. if rcd = 19.2,
the total series resistance r to outdoors is 19.2/475 = 0.0404 fh/btu,
and 1/q = 0.04040.00506 = 0.035 fhub. q = 28.6 cfm = 16.6asqrt(8'(70.666))
makes a = 0.28 ft^2 for natural airflow. we could cool 2" of water above
the ceiling with a gable vent or a thermal chimney above a flat roof.
we could also use a fan (an exhaust fan that moves the motor heat outdoors.)
in pablo laroche and murray milne's tiny ucla test houses with thermal mass,
a "smart whole house fan controller" turned on a fan when outdoor air was
cooler than indoor air. "enthalpy economizers" do this for large buildings,
but seldom for houses. with a humidity sensor, we might heat as well as cool
a house by ventilation, and avoid condensation on mass surfaces, and bias
the house temperature into the upper part of the comfort zone in wintertime
and the lower part in summertime in order to store more heat or coolth in
the house mass. brand electronics may soon sell such a fan controller.
we might also cool 2" of water above the ceiling with a roof pond, as in a
zomeworks thermosyphoning "architectural cool cell." phil niles says a t (f)
pond in to (f) air loses 1.63x10^9((t+460)^4a(to+460)^4) btu/hft^2 by
radiation, where a = 0.002056tdp+0.7378, with a dew point temp tdp (f). in
a v mph wind, it also loses qc = (0.74+0.3v)(tto) btu/hft^2 by convection
and evaporates qe = b(ttwb)qc, where b = 3.01(0.74+0.3v)((t+twb)/651),
and twb (f) is the wet bulb temperature.
the pond radiates more heat to the sky if the air contains less moisture,
with a higher dew point, since water vapor is a "greenhouse gas" that blocks
radiation. air at the dew point temperature is saturated with water vapor.
the relative humidity is 100%. we can find the approximate dew point by
first finding the vapor pressure of water in air on an average july day in
boulder with humidity ratio w = 0.009. pa = 29.921/(1+0.62198/w) = 0.427" of
mercury ("hg29.921 "hg is 1 atmosphere.) then we use a clausiusclapeyron
approximation (don't ask) to find the temperature corresponding to that
pressure, at 100% rh. if pa = e^(17.8639621/tdp), ln(pa) = 17.8639621/tdp,
so tdp = 9621/(17.863ln(pa)) = 514 r or 54 f in boulder in july.
this makes a = 0.7399 in the formula above, so a 70.6 f pond in 58.6 f night
air would lose 1.63x10^9((70.6+460)^40.7399(58.6+460)^4) = 42 btu/hft^2.
nrel says the average july windspeed in boulder is 8.1 mph, so a pond would
lose (0.74+0.3x8.1)(70.658.6) = 38 btu/hft^2 by convection. an 8'x8' roof
pond would lose 8x8(42+38) = 5120 btu/h by radiation and convection, more
than a 5k btu/h window air conditioner. keeping the cube 72.6 f on an 81 f
day in boulder only requires 12h(8172.6)19.2 = 1935 btu, so we don't need
to evaporate water from this roof pond. it might have a polyethylene film
cover, since poly film is essentially transparent to radiation.
the dew point temperature only depends on the amount of water in an air
sample, vs its temperature. a little water inside a perfectlyinsulated cup
might find itself at the dew point temp, as water evaporates from the
surface and water vapor molecules diffuse to the top of the cup, while
the air above the water acts as a good insulator (about r5 per inch for
downward heatflow.) which water depth will keep it coolest in an r5 3"
diameter x 6" tall cup? as we fill the cup, the air layer insulates less,
but more water evaporates, according to fick's law, since the concentration
gradient increases as the air layer thins...
when the water gets to the top of the cup, we'd expect to see it at the wet
bulb temperature, when its heat loss by evaporation equals its heat gain by
convection. a perfect swamp cooler would make air at this temperature. in
1926, i.s. bowen said a pond's ratio of heat loss by evaporation to heat
gain by convection equals 100(pppa)/(tpta), regardless of windspeed. this
is 1 at the wet bulb temp. with pa = 0.009, and ta = 58.6 f, and tw (r),
100(e^(17.8639621/tw)0.427) = 58.6+460tw, so tw = 9621/(22.47ln(561.3tw)).
the wet bulb temp is easy to find on a calculator. plugging in tw = 518.6 r
(58.6 f) on the right of the equation above makes tw = 514 on the left.
doing this again makes tw = 517, 515, 516.2, 515.6, 515.9, 515.7, and 515.8
(55.8 f), between the dew point and dry bulb temperatures. so an uncovered
pond would lose qe = b(ttwb)qc, where b=3.01(0.74+0.3x8.1)((70.6+55.8)/651)
= 9.01 and qe = 9.01(70.655.8)38 = 95 more btu/hft^2 by evaporation, like
a 10k btu/h window ac. this could be useful in phoenix. one simple ashrae
swimming pool formula says q = 100(pwpa) btu/hft^2, regardless of air
temp. pw = e^(17.8639621/(460+70.6)) = 0.764 "hg and pa = 0.427 "hg makes
q = 34 btu/hft^2.
indoor misting with a vent fan for outdoor air works like a swamp cooler,
when 4500(wiwo)>toti. the left side is the amount of latent cooling per
cfm of vent air. the right is the amount of sensible heating per cfm of
vent air. as they become equal, swamp cooling and misting no longer work.
my 29 jan 2005 posting "expanding ashrae comfort zones" in the workshop cd
postlog file has the basic program used to calculate comfort levels from the
ashrae 552004 standard. the ashrae comfort zone ( has an efficient corner
at ti = 80.2 f and wi = 0.012 (at 56% rh), which makes to < 134.24500wo.
nrel says phoenix has an 88.2 f average temp in june, with an average daily
min and max of 72.9 and 103.5 and humidity ratio wo = 0.0056 pounds of water
per pound of dry air in june, so misting should help until the outdoor temp
rises to to = 134.24500(0.0056) = 109 f. innova airtech instruments has
a good comfort web site: http://www.impind.de.unifi.it/impind/didattica/
materiale/microclima/innova/thermal.htm.
evaporating a pound of water takes about 1000 btu, and air weighs about
0.075 lb/ft^3, so a house with no internal heat gain or unshaded windows
and a 200 btu/hf conductance that's 80.2 f indoors with wi = 0.012 when
it's 88.2 f and wo = 0.0056 outdoors needs 1000x60c0.075(0.0120.0056)
= 28.8c = (88.280.2)(200+c) btu/h of cooling, including cooling c cfm of
air from 88.2 to 80.2, so c = 77 cfm (not much), with 4.5c(0.0120.0056)
= 2.2 pounds or 0.27 gph of water, which might come from a $5 0.5 gph
mister mister nozzle and a solenoid valve scrounged from an old washing
machine in series with a 80.2 f room temp thermostat and a $5 humidistat
that turns on a $12 window exhaust fan when the rh rises to 56%.
we can make 77 cfm move through the house with a ft^2 vents with an 8'
height difference if 77 = 16.6asqrt(8(88.280.2)), ie a = 0.58 ft^2, eg
a 1 ft^2 vent to the attic, to keep it cooler. the 2.2lb/h of water might
come from plants in an indoor greywater wetland. with enough plants,
the thermostat may never turn on the mister. in an airleaky house,
the humidistat may never turn on the fan.
grainger's $28.10 2e453 autoflo humidistat has a 1060% range
and a 46% differential and a 120v 4.4 a switch.
pw = 1.033 "hg at 80.2 f and 100% rh, and pi = 0.566 "hg with wi = 0.012.
ashrae says a square foot of pool evaporates 100(pwpi) = 47 btu/h, so we
can evaporate 2.2 pounds of water per hour with 2200/47 = 47 ft^2 of wet
surface, counting droplets in air, or less, if we evaporate close to the
house air inlet. masonry floors and walls or an indoor cylindrical rock
gabion with a fountain pump (in a toilet tank?) with a high conductance
and mass might allow more efficient cooling with cooler night air and keep
the house mass cool with the fan off during the heat of the day. the gabion
might make an interesting mineral encrustation that helps evaporate water.
exercise 14.1: how many gph and cfm and square feet are needed if the house
has 1000 btu/h of internal heat gain and 400 btu/hf of conductance and
outdoor air enters the top of a gabion and leaves via the sides?
in arid places like phoenix, why not distill the water we drink
in a greenhouse and filter the rest through a hightemp wetland?
nrel says 1020 btu/ft^2 of sun falls on the ground and 1550 falls on a south
wall on an average 53.6 f january (the worstcase month for solar heating)
day in phoenix. a 16'x16'x8' tall greenhouse would get 0.8(256x1020+128x1550)
= 368k btu of sun. distilling 10 gallons of potable water at 1,000 btu/lb
(or a lot less, with steve baer's multieffect still) would leave 368k83k
= 284k btu. with 600 ft^2 of r1.2 surface, the greenhouse conductance would
be 500 btu/hf, so 284k btu could keep it 53.6+284k/(24hx500) = 80 f (27 c)
on an average day.
we might put a outer layer of plastic film over 4 16' long x 8' tall outer
bows and another layer over 4 inner bows, with a slot at the top to allow
warm moist air to enter the space between films and condense water into east
and west troughs on the ground made from a fold in the outer layer, with
a slot in the inner layer above the trough to allow air to recirculate.
if 80 f air enters the top at 100% rh with wt = 0.0226 and 53.6 f air leaves
the bottom at 100% with wb = 0.0088, distilling 10 gallons in 24 hours means
24x60c0.075(wtwb) = 1.48c = 10x8.33, so c = 56 cfm = 16.6asqrt(8x(8053.6)),
for an upper vent area a = 0.23 ft^2, eg 3 4" holes. the inner films might
have 3 2" holes near the ground. the troughs might also collect rainwater,
if any. the greenhouse might have a gravel bed over an epdm rubber layer
to make an artificial wetland.
metcalf and eddy say an average family produces 400 gallons per day of
wastewater with a 200 mg/l bod concentration, ie about 0.7 lb/day, and it
needs about 175 ft^2 of surface for treatment. sherwood reed says blackwater
contains more than 75% of the nitrogen in only 40% of the flow. eliminate
that with a composting toilet or solar poop cooker, and we might only treat
240 gallons per day (0.908 m^3/day) with 0.175 lb of bod, ie 86 mg/l.
can we purify this to 10 mg/l (a tertiary sewage treatment standard)
and recycle it for nonpotable uses? pe sherwood reed's natural systems
for waste management and treatment book (mcgraw hill, 2nd edition, 1995)
has a detailed design procedure for constructed wetlands, aka "attached
growth biological reactors." they work well at higher temperatures.
equation 6.38 on page 226 of reed's book says the rate constant for
bod removal in subsurfaceflow wetlands at 20 c is k20 = 1.104d^1.
equation 6.34 makes k27 = 1.104x1.06^(2720) = 1.66d^1 at 27 c. we
need to reduce the bod from co = 86 to ce = 10 mg/l with 256 ft^2
(23.8 m^2) of surface. if the bed is "medium gravel" (d10 = 32 mm)
with a 0.38 porosity, it needs to be 0.908ln(co/ce)/(k27x23.8x0.38)
= 0.13 meters deep, ie 5.1 inches. we might add gravel or divide
the bed into 3 series cells for better plug flow and performance.
what will grow in this rainforest? orchids? mangos? bananas? :)
if we must use an air conditioner, why not mist the air around the hot coils
or trickle rainwater over them? d. y. goswami at u. florida measured a 20%
gain in ac efficiency as a result of misting the air around the hot coil.
i've measured 20% by trickling rainwater over a window unit.
a more sophisticated cooling system with no water consumption or outdoor air
exchange might have a multieffect licl solar still on the roof that absorbs
water vapor at night from the pond below and distills water out of the licl
solution during the day. this might also store cloudy day heat, with a wet
basement floor to evaporate water in wintertime, and a licl pond on the
first floor that acts as a "chemical heat pump."
nick
answers to exercises
0.1: if the current gulf war costs $400 billion per year, and we consume
26millionx42gx365d = 399 billion gallons per year, a gallon of oil costs
400billion/399billion = $1 plus the pump price. if 38,000 people per year
die prematurely because of pollution from oil burning, at $1 million per
death, that would add $38 billion, ie another 10 cents. what's the cost of
acid rain? low pump prices that only reflect part of the real costs send
the wrong market message to consumers, who would conserve more if they
paid the whole cost at the pump.
0.2: a) if both work for 4 hours per day and the cf costs $5 and lasts
10,000 vs 1000 hours and the pvs cost $8/wx46w = $368.
1.1: c = 1/2 pound x 1 btu/lbf = 0.5btu/f [c = 0.25 kg x 4.19 kj/kgc
= 1.05 kj/c], and dt = 212f50f = 162 f [dt = 100c10c = 90c], so we need
cdt = 81 btu [94.5 kj], if the water is heated quickly, so most of the heat
stays in the water and little heat flows into the room.
1.2: 81btux60m/h/(300wx3.41btu/hw) = 4.8 minutes.
[94.5kj/3600j/wh/300wx60m/h = 5.3 minutes.]
2.1: 12v/24a = 0.5 ohms.
3.1: r = dt/i = 12f/6btu/h = 2 fh/btu (fhubs.) [7w/2c = 3.5w/c.]
3.2: 8'x16'/r10 = 12.8 btu/hf (buhfs.) [2mx5m/r2 = 5 w/c.]
3.3: [20cx2mx6mxu0.5 = 120 watts.] 36fx8’x16’xu0.088 = 405 btu/h.
3.4: (70f30f)3'x4'xu0.25btu/hfft^2 = 120 btu/h. an r8 hurd heat mirror
window would only pass 60 btu/hft^2. csash makes lowe storm windows...
3.5: 40fx24'x32'/r64 = 480 btu/h. [22cx7mx10mxu0.089 = 137 w.]
4.1: 350 btu/h = (70f30f)6l^2/r10 makes l = sqrt(350/24) = 3.82 feet, max.
4.2: with 1 dog, l = sqrt(450/12) = 6.1'. with 2, l = sqrt(550/12) = 6.8'
....3 make l = 7.4'. with r50 strawbales, 650 btu/h = (7030)6l^2/r50 makes
l = 11.6 feet. an lxlx8' tall room with 650 = (7030)(2l^2+4x8l)/r50 has
l^2+16l406.25 = 0, so l = (16+sqrt(16^24(406.25))/2 = 13.7'.
4.3: l = 24/13.2 = 1.8', say 2’, with 64 mice in 8 rooms.
4.4: 774l^3/(1024x8) = (7030)6l^2/r20 makes l = 127' min, eg a 128'
16story cube with 256 families, like the borg, or a large anthill.
5.1: if 0.8x1000x4ft^2/24h = 133 btu/h = (t30f)(4ft^2/r2+(6x8'x8'4)/r20)
= 12(t30), t = 30 + 133/12 = 41 f. [if 0.8x3.15kwhx0.4m^2/24h = 42 w
the answer is always 42) = (t(1))(0.4m^2/r0.4+(6x2mx2m0.4)/r4) =
6.9(t+1), t = 1 + 42/6.9 = 5 c. not very warm.
5.2: if 0.8x800 = 640 btu/ft^2day of solar energy comes in the window and
640a/24h = 26.7a = (7031.8)(a/2+(6x64a)/r20) = 17.2a + 733 btu/h leaves,
a = 77 ft^2, which is larger than the cube wall, so (surprise) we can't have
a direct gain 100%solarheated house in allentown even on an average vs
cloudy day, without more insulation or mice or people or electrical use.
6.1: t(1) = 30+(7530)e^(1) = 46.6 f.
6.2: c = 6x8x8/2 = 192 btu/f. g = 6x8x8/20 = 19.2 btu/hf. rc = c/g
= 10 hours. t(9) = 30+(7030)e^(9/10) = 46.3 f. adding 1000x5 btu/f makes
c = 5019 and c/g = 261 h and t(9) = 30+(7030)e^(9/261) = 68.6 f, which
is good for direct gain, but bad for night setback savings.
6.3: rc = 8x8x8x64/19.2 = 1707 hours makes t(9) = 30+(7030)e^(9h/1707h)
= 69.8 f. t(5 days) = 67.3, and after 2 cloudy weeks, t = 62.9. this is
a good solar house, for a fish, but with no windows, how can we heat it?
7.1: on a cloudy day, with no sunspace airflow, the r20 cube in section 5
with an r20 wall between the cube and the sunspace would have a conductance
of 6x64/r20 = 19.2 vs 48 btu/hf, with rc = 4.4n/19.2/24h = 0.00955n days.
starting at 75 f, t(5d) = 65 = 30+(7530)e^(5/0.00955n) 5 days later, so
523.6/n = ln((6530)/(7530)), and n = 2083, only 45% of the cube’s volume.
8.1: the 0.08x40x60 = 192 ft^2 of windows have 192ft^2/r4 = 48 btu/hf.
the 2(40+60)8192 = 1408 ft^2 of nonwindow wall surface adds 1408/30
= 47, the ceiling adds 2400/60 = 40, and 0.5x2400x8/60 = 160 cfm, or about
160 btu/hf, over 10x the 15 cfm/occupant ashrae ventilation standard.
the total is 295, of which 54% comes from air leaks and 16% comes from
windows. why do houses need windows, vs flatscreen tvs?
9.1: ignoring sunspace vent and ceiling resistances, an 8' r32 cube
with a ceiling temp t (f) and 8'x8' of r2 80% sunspace glazing might
collect 0.8x470x64 = 24064 btu and lose about 6h(t40.2)64ft^2/r2 from
the glazing during the day + 18h(6540.2)64ft^2/r32 from glazing at night
+ 24h(t40.2)64ft^2/r32 from the ceiling + 24h(6540.2)3x64ft^2/r32 from
the other walls at night, which makes t = 121.9 f, if gain equals loss
on an averageday.
if the ceiling conductance to slowmoving air below is 1.5x64 = 96 btu/hf,
and the cube needs (7040.2)4x64/32 = 238 btu/h of heat (less than 1 human),
the min ceiling temp is 70+238/96 = 72.5 f. the average is (121.9+72.5)/2
= 97.2. if the cube loses 5x24h((6540.2)4x64ft^2/r32+(97.240.2)64ft^2/r32)
= 37.49k btu over 5 days, we need 37.49k/(121.972.5) = 758.9 btu/f, eg
758.9/64 = 11.9 pounds (2.22") of water per square foot of ceiling.
or less, using the differential equation. at ceiling temperature t,
i = (t40.2)64ft^2/r32 + (6540.2)4x64ft^2/r32 = 2t + 118 btu/h flows
from c, so dt/dt = i/c = 2t/c  118/c, and 118/2 = 59. after 5 days,
t(t) = 72.5 = 59 + (121.9+59)e^(2x120/c), so c = 240/ln(131.5/180.9)
= 752 btu/f, ie 752/64/64x12 = 2.20" of water.
9.2: i = (t40.2)64ft^2/r32 + 8/24(6540.2)4x64ft^2/r32 = 2t14.3
btu/h flows from c, so dt/dt = i/c = 2t/c + 14.3/c, and 14.3/2 = 7.1.
t(t) = 72.5 = 7.1 + (121.97.1)e^(2x120/c) makes c = 240/ln(65.4/114.8)
= 427 btu/f, ie 427/64/64x12 = 1.25" of water.
10.1: 300 btu/h = 0.1714x10^8x0.2(t^4(460+20)^4) makes t = 982 r or 522 f.
13.1: i = (7030)200 = 8k btu/h. t = 70 + i/(2400x1.5) = 72.2 f.
14.1: if 28.8c = 1000+(88.280.2)(400+c), c = 202, with 4.5c(0.0120.0056)
= 5.8 pounds or 0.70 gph of water. pw = 1.033 "hg at 80.2 f and 100% rh, and
pi = 29.921/(0.62198/0.0056+1) = 0.267 "hg with wi = 0.0056 and 100(pwpi)
= 77 btu/hft^2 make 5800/77 = 76 ft^2 of wet surface. a 3" sphere has about
4pir^2 = 0.196 ft^2 of surface, or 0.196x4^3 = 12.6 ft^2/ft^3, so we need
7.1 ft^3 of 3" rocks, eg a 2' diameter x 3' tall hollow gabion with a $10
10 watt fountain pump and a float valve in the bottom.

